Next number is 312211
Solution: You get next number by finding how many of each digit present in the previous number
1st number is 1
2nd number is 11 i.e., no. of 1’s in previous number which is “ONE 1” so 11
3rd number is 21 i.e., in previous number we have “one 2 and one 1” so 1211
4th number is 111221 i.e., in previous number we have “one 1, one 2 and 2 one” so 111221
and so on

It is called a “look-and-say sequence” in Mathematics
The look-and-say sequence was introduced and analyzed by John Conway in his paper “The Weird and Wonderful Chemistry of Audioactive Decay” published in Eureka 46, 5–18 in 1986.

(A). The first sequence is created based on the first letters of Months.
So, J for January, F for February and so ON.
So, The correct sequence is J,F,M,A,M,J,J

(B). Consider the sequence 1,2,3,4,5,6,7
Now, Number of letters in 1- three(3)
No. of letters in 2- three(3)
In 3- five(5)
In 4- four(4),
In 5-4,
In 6-3,
In 7-5
So, the Series becomes, 3,3,5,4,4,3,5.

(C). This one is difficult but use your intuition.
It starts with only one 1, then it becomes one one (11), Now there are two ones (21), Now one two & one one(1211),one one & one two & two one(111221), Finally it becomes three one & two two & one one (312211).
So, Answer is 312211

The Sequence is first letter of the months ‘J’anuaray, ‘F’ebruary, ‘M’arch, ‘A’pril, ‘M’ay,’J’une,’J’uly etc

Answer to question #2 is “5?

You will get the sequence by Counting the letters in one, two, three, four, five, six, seven, eight, and so on i.e. 3, 3, 5, 4, 4, 3, 5 ,5 etc

Answer to question #3 is “312211?

Pattern:
1 is read off as “one 1? or 11.
11 is read off as “two 1s” or 21.
21 is read off as “one 2, then one 1? or 1211.
1211 is read off as “one 1, then one 2, then two 1s” or 111221.
111221 is read off as “three 1s, then two 2s, then one 1? or 312211.

Mohammed Najeeb ur RahmanDecember 9, 2013 at 12:23 PM#

The Sequence is first letter of the months ‘J’anuaray, ‘F’ebruary, ‘M’arch, ‘A’pril, ‘M’ay,’J’une,’J’uly etc

Answer to question #2 is “5?

You will get the sequence by Counting the letters in one, two, three, four, five, six, seven, eight, and so on i.e. 3, 3, 5, 4, 4, 3, 5 ,5 etc

Answer to question #3 is “312211?

Pattern:
1 is read off as “one 1? or 11.
11 is read off as “two 1s” or 21.
21 is read off as “one 2, then one 1? or 1211.
1211 is read off as “one 1, then one 2, then two 1s” or 111221.
111221 is read off as “three 1s, then two 2s, then one 1? or 312211.

The Sequence is first letter of the months ‘J’anuaray, ‘F’ebruary, ‘M’arch, ‘A’pril, ‘M’ay,’J’une,’J’uly etc

Answer to question #2 is “5”

You will get the sequence by Counting the letters in one, two, three, four, five, six, seven, eight, and so on i.e. 3, 3, 5, 4, 4, 3, 5 ,5 etc

Answer to question #3 is “312211”

Pattern:
1 is read off as “one 1? or 11.
11 is read off as “two 1s” or 21.
21 is read off as “one 2, then one 1? or 1211.
1211 is read off as “one 1, then one 2, then two 1s” or 111221.
111221 is read off as “three 1s, then two 2s, then one 1? or 312211.

Pattern:
1 is read off as “one 1” or 11.
11 is read off as “two 1s” or 21.
21 is read off as “one 2, then one 1” or 1211.
1211 is read off as “one 1, then one 2, then two 1s” or 111221.
111221 is read off as “three 1s, then two 2s, then one 1” or 312211.

Ans1. J

Ans 2. 551

Ans3. 312211

J

5

Can any one guide me regarding the Qs # 3 please?

Next number is 312211

Solution: You get next number by finding how many of each digit present in the previous number

1st number is 1

2nd number is 11 i.e., no. of 1’s in previous number which is “ONE 1” so 11

3rd number is 21 i.e., in previous number we have “one 2 and one 1” so 1211

4th number is 111221 i.e., in previous number we have “one 1, one 2 and 2 one” so 111221

and so on

It is called a “look-and-say sequence” in Mathematics

The look-and-say sequence was introduced and analyzed by John Conway in his paper “The Weird and Wonderful Chemistry of Audioactive Decay” published in Eureka 46, 5–18 in 1986.

I agreewith sk ashif

1). J

2). 5

3). 2112211

Third one is wrong

1) J (uly)

2) 5 (5,1,6,………….)

3) 1 11 21 2 1211, 1 11 21 1211 2 111221, 1 11 21 1211 111221 2 1112121211,…..

J for July

5 number of letters of the number seven

312211

(A) : J

(B) : 5

(C) : 312211

Right answers 🙂

(A). The first sequence is created based on the first letters of Months.

So, J for January, F for February and so ON.

So, The correct sequence is J,F,M,A,M,J,J

(B). Consider the sequence 1,2,3,4,5,6,7

Now, Number of letters in 1- three(3)

No. of letters in 2- three(3)

In 3- five(5)

In 4- four(4),

In 5-4,

In 6-3,

In 7-5

So, the Series becomes, 3,3,5,4,4,3,5.

(C). This one is difficult but use your intuition.

It starts with only one 1, then it becomes one one (11), Now there are two ones (21), Now one two & one one(1211),one one & one two & two one(111221), Finally it becomes three one & two two & one one (312211).

So, Answer is 312211

You have given all correct answers 🙂

1- J

2 -5

3- 211221

Answer to question #1 is “J”

The Sequence is first letter of the months ‘J’anuaray, ‘F’ebruary, ‘M’arch, ‘A’pril, ‘M’ay,’J’une,’J’uly etc

Answer to question #2 is “5?

You will get the sequence by Counting the letters in one, two, three, four, five, six, seven, eight, and so on i.e. 3, 3, 5, 4, 4, 3, 5 ,5 etc

Answer to question #3 is “312211?

Pattern:

1 is read off as “one 1? or 11.

11 is read off as “two 1s” or 21.

21 is read off as “one 2, then one 1? or 1211.

1211 is read off as “one 1, then one 2, then two 1s” or 111221.

111221 is read off as “three 1s, then two 2s, then one 1? or 312211.

C-1111221211

Answer to question #1 is “J”

The Sequence is first letter of the months ‘J’anuaray, ‘F’ebruary, ‘M’arch, ‘A’pril, ‘M’ay,’J’une,’J’uly etc

Answer to question #2 is “5?

You will get the sequence by Counting the letters in one, two, three, four, five, six, seven, eight, and so on i.e. 3, 3, 5, 4, 4, 3, 5 ,5 etc

Answer to question #3 is “312211?

Pattern:

1 is read off as “one 1? or 11.

11 is read off as “two 1s” or 21.

21 is read off as “one 2, then one 1? or 1211.

1211 is read off as “one 1, then one 2, then two 1s” or 111221.

111221 is read off as “three 1s, then two 2s, then one 1? or 312211.

Guys who has the logic or the equation please send to me in replay.

Thx

Answer to question #1 is “J”

The Sequence is first letter of the months ‘J’anuaray, ‘F’ebruary, ‘M’arch, ‘A’pril, ‘M’ay,’J’une,’J’uly etc

Answer to question #2 is “5”

You will get the sequence by Counting the letters in one, two, three, four, five, six, seven, eight, and so on i.e. 3, 3, 5, 4, 4, 3, 5 ,5 etc

Answer to question #3 is “312211”

Pattern:

1 is read off as “one 1? or 11.

11 is read off as “two 1s” or 21.

21 is read off as “one 2, then one 1? or 1211.

1211 is read off as “one 1, then one 2, then two 1s” or 111221.

111221 is read off as “three 1s, then two 2s, then one 1? or 312211.

A.F

B.3

C.11112211

A- A

B- 2

C- 1112111

Answer for #3 is 312211

Pattern:

1 is read off as “one 1” or 11.

11 is read off as “two 1s” or 21.

21 is read off as “one 2, then one 1” or 1211.

1211 is read off as “one 1, then one 2, then two 1s” or 111221.

111221 is read off as “three 1s, then two 2s, then one 1” or 312211.